today:
5
yesterday:
242
Total:
1,004,163

SQL EMPLOYEE_LEVEL_ID

admin 2016.05.03 19:45 Views : 89

declare
  v_access_level  number;

begin
  select e.employee_level_id  into  v_access_level
   from EMP  e
   where  lower(e.ou_name) = lower ('&USER.');
  if  v_access_level in (1,4)  then
      return  true;
      else
      return false;
  end if;

 EXCEPTION
      WHEN NO_DATA_FOUND
      THEN
         RETURN false; 
end;

No. Subject Author Date Views
41 ACTION admin 2019.01.11 6456
40 GP PRINT admin 2018.05.31 918
39 INSTR admin 2016.05.19 789
38 SELECT last_name FROM admin 2018.12.12 742
37 TREE admin 2016.05.18 722
36 CREATE TABLE admin 2018.09.25 471
35 SQL admin 2016.07.15 396
34 DATE Compare admin 2018.05.22 366
33 SUBSTR admin 2016.05.26 272
32 FOR LOOP admin 2016.05.20 269
31 ROWNUM admin 2016.05.19 240
30 Group by, Order by (두개의 Table을 활용한 Sub Total / 최고값 ) admin 2016.05.06 234
29 VERY IMPORTANT admin 2018.06.26 226
28 Report by Order / Product / Order and Product / By Order & Non Order admin 2016.04.29 220
27 CREATE VIEW admin 2016.05.13 218
26 Name Show admin 2016.04.28 203
25 MISSIONARY_SUB admin 2018.06.25 199
24 How to convert DATE to NUMBER admin 2018.05.27 198
23 TABLE PRINT admin 2018.06.18 186
22 CREATING A TABLE / SEQUENCE / TRIGGER admin 2016.04.28 172