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SQL SQL

admin 2016.07.15 23:37 Views : 396

select 
null, '#' || g.SGROUP_ID "SGROUP_ID",
t.IMEMBER_SK, t.SMEMBER_ID, t.SFAMILY_ID, t.ISORT_ID, t.SFAMILYRELATION_ID,
 t.SNATIVE_NM || '' ||    case 
when substr (g.SGROUP_ID,4,1) = '1'and substr (g.SGROUP_ID,5,1) is null and t.GROUP_SORT_KEY = 'Y'
 then ' <htmL><b><font color="Red"> *** </font></b></html>' 

when t.GROUP_LEADER_KEY = 'Y' then ' <htmL><b><font color="Red"> ** </font></b></html>'  

when t.GROUP_SORT_KEY = 'Y'  then '<htmL><b><font color="Red"> * </font></b></html>' else '  '  end SNATIVE_NM,  
   
case  when substr (t.STELPERSONAL, 1,3) = '111'  then '<htmL><blink><font color="Red">Not Provided</font></blink></html>'   else to_char (t.STELPERSONAL)  end  as STELPERSONAL,

case when t.IBIRTH_DT = 0 or t.IBIRTH_DT = 11111111 then '<htmL><blink><font color="Red">Not Provided</font></blink></html>' else to_char (substr(t.IBIRTH_DT,5,2)) || '/' || to_char (substr(t.IBIRTH_DT,7,2)) || '/' || to_char (substr(t.IBIRTH_DT,1,4)) END as "IBIRTH_DT", 
   
CASE  when t.STITLE = '' or substr(t.STITLE,1,1) = '%' then '-'  ELSE to_char (t.STITLE ) END  AS Title, t.ILEADMEMBER_SK ,  tt.SNATIVE_NM  as Leader
from TBLCHURCHMEMBER t,   TBLGROUP g, TBLCHURCHMEMBER tt
where   
  t.GROUP_CELL_FLAG = 'Y'  
and substr(t.SMEMBER_ID,6,2) in ('HD','SP','P1','P2')
and t.ICELLGROUP_SK =  g.IGROUP_SK 
and substr( g.SGROUP_ID,1,1) != '9'
and t.ILEADMEMBER_SK = tt.IMEMBER_SK
order by  "SGROUP_ID", t.GROUP_SORT_KEY, "SFAMILY_ID", "SFAMILYRELATION_ID")
No. Subject Author Date Views
41 ACTION admin 2019.01.11 6456
40 GP PRINT admin 2018.05.31 918
39 INSTR admin 2016.05.19 789
38 SELECT last_name FROM admin 2018.12.12 742
37 TREE admin 2016.05.18 722
36 CREATE TABLE admin 2018.09.25 471
» SQL admin 2016.07.15 396
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