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SQL SQL

admin 2016.07.15 23:37 Views : 388

select 
null, '#' || g.SGROUP_ID "SGROUP_ID",
t.IMEMBER_SK, t.SMEMBER_ID, t.SFAMILY_ID, t.ISORT_ID, t.SFAMILYRELATION_ID,
 t.SNATIVE_NM || '' ||    case 
when substr (g.SGROUP_ID,4,1) = '1'and substr (g.SGROUP_ID,5,1) is null and t.GROUP_SORT_KEY = 'Y'
 then ' <htmL><b><font color="Red"> *** </font></b></html>' 

when t.GROUP_LEADER_KEY = 'Y' then ' <htmL><b><font color="Red"> ** </font></b></html>'  

when t.GROUP_SORT_KEY = 'Y'  then '<htmL><b><font color="Red"> * </font></b></html>' else '  '  end SNATIVE_NM,  
   
case  when substr (t.STELPERSONAL, 1,3) = '111'  then '<htmL><blink><font color="Red">Not Provided</font></blink></html>'   else to_char (t.STELPERSONAL)  end  as STELPERSONAL,

case when t.IBIRTH_DT = 0 or t.IBIRTH_DT = 11111111 then '<htmL><blink><font color="Red">Not Provided</font></blink></html>' else to_char (substr(t.IBIRTH_DT,5,2)) || '/' || to_char (substr(t.IBIRTH_DT,7,2)) || '/' || to_char (substr(t.IBIRTH_DT,1,4)) END as "IBIRTH_DT", 
   
CASE  when t.STITLE = '' or substr(t.STITLE,1,1) = '%' then '-'  ELSE to_char (t.STITLE ) END  AS Title, t.ILEADMEMBER_SK ,  tt.SNATIVE_NM  as Leader
from TBLCHURCHMEMBER t,   TBLGROUP g, TBLCHURCHMEMBER tt
where   
  t.GROUP_CELL_FLAG = 'Y'  
and substr(t.SMEMBER_ID,6,2) in ('HD','SP','P1','P2')
and t.ICELLGROUP_SK =  g.IGROUP_SK 
and substr( g.SGROUP_ID,1,1) != '9'
and t.ILEADMEMBER_SK = tt.IMEMBER_SK
order by  "SGROUP_ID", t.GROUP_SORT_KEY, "SFAMILY_ID", "SFAMILYRELATION_ID")
No. Subject Author Date Views
21 TREE admin 2016.05.18 722
20 INSTR admin 2016.05.19 785
19 NVL admin 2016.05.19 151
18 ROWNUM admin 2016.05.19 240
17 FOR LOOP admin 2016.05.20 268
16 SUBSTR admin 2016.05.26 271
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