SELECT distinct c.CUSTOMER_ID , initcap(C.CUST_FIRST_NAME || ' ' || C.CUST_LAST_NAME) Name, o.ORDER_ID, O.ORDER_TOTAL
FROM DEMO_CUSTOMERS C, DEMO_ORDERS O, DEMO_ORDER_ITEMS I
where C.CUSTOMER_ID = O.CUSTOMER_ID and
I.ORDER_ID = O.ORDER_ID
------------------------------------------------------
* SQL SELECT DISTINCT Statement
In a table, a column may contain many duplicate values; and sometimes you only want to list the different (distinct) values.
The DISTINCT keyword can be used to return only distinct (different) values.
No. | Subject | Author | Date | Views |
---|---|---|---|---|
126 | LAST DAY SQL | admin | 2024.01.19 | 115 |
125 | Null Display Value | admin | 2024.01.10 | 111 |
124 | 영수증 2023 | admin | 2024.01.04 | 223 |
123 | Column Data 일괄 추가 | admin | 2023.11.24 | 130 |
122 | Using SQL*Plus to Unlock and Change Passwords | admin | 2023.06.04 | 150 |
121 | Reversing Require HTTPS | admin | 2023.06.04 | 84 |
120 | ipconfig | admin | 2023.06.03 | 67 |
119 | 127.0.0.1:8080/apex/ | admin | 2023.06.03 | 83 |
118 | CHANGE TABLE NAME | admin | 2023.05.31 | 58 |
117 | DATE -> DAY CONVERT SQL | admin | 2023.05.25 | 38 |
116 | YEAR EXPRESSIONS | admin | 2023.05.25 | 34 |
115 | GRAPH (BAR) SQL SAMPLE | admin | 2023.05.25 | 39 |
114 | Monthly SUM | admin | 2023.05.22 | 37 |
113 | INNER JOIN | admin | 2023.05.19 | 37 |
112 | LOOP TABLE UPDATE | admin | 2023.05.19 | 50 |
111 | Global pages | admin | 2023.05.09 | 40 |
110 | ORACLE COLLECTION | admin | 2023.05.08 | 38 |
109 | FINAL TEST | admin | 2023.05.08 | 44 |
108 | GitHub.com/Oracle/APEX. | admin | 2023.05.04 | 40 |
107 | TEST | admin | 2023.05.03 | 36 |